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10m^2+37m=0
a = 10; b = 37; c = 0;
Δ = b2-4ac
Δ = 372-4·10·0
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-37}{2*10}=\frac{-74}{20} =-3+7/10 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+37}{2*10}=\frac{0}{20} =0 $
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